The resistance of the coil is proportional to its length because the total resistance is just the two halves placed in series. This means that each half of the coil has half the original resistance. Let's call the original resistance R. The new resistance is R/2. The applied voltage is constant, because it is based on the line voltage, call it V.
The original power dissipated is P = V2/R (heat produced = power dissipated)
After cutting in half, the power dissipated is V2/(R/2) = 2V2/R = 2P
So the power output has doubled. This seemingly paradoxical result can be understood by the fact that a short circuit with no resistance will generate a lot of heat! And by shortening the coil, we are getting closer to a short circuit.
However, in a real heater, this would cause the element to get much hotter, and as its temperature increases, its resistance would also increase. So the result would not hold for a real system.
Resistance is halved, so current, (load drawn), doubles.
It will likely fail due to overheating in short order.
Heat produces close to double but it shall burn away within a few minutes.
The resistance will be cut in half.
the heat will be doubled......... as power desipated= heat produced so the huge amount of heat will generate and the wire will burn................
What will happen to the heat produced? and why?
