a) p=vr^2, r=(p/v)^.5=3.53 ohm
b) p;=v*i, i=p/v=12.5
Np/Ns=Vp/Vs=120/16=7.5
Vp=120V, Vs/Vp=0.05, Vs=0.05*120V=6V
Ns=200*768=153,600 turns
A) Ns=Np*(Vs/Vp)=0.1*Np, Np is not given
B) P=VI, 6=12*I, I=0.5A
f=1/[2*pi*([LC)^.5)]=1453 Hz
Vp=sqrt(2)*Vrms
P=V^2/R or R=V^2/P
Ns=200*768/1
Vs/Vp=Ns/Np
Pprimary=Psecondary.
20/120=.167
120 x 1.4 = 168
Strictly speaking, it is not 1.4 but 1.4142135623730950488016887242097.... = SQRT[2]
This is only about 1% difference, though
What is the peak voltage corresponding to 120 V rms?
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