where A = current
V= voltage
W =watts,
now add the watts of two bulbs which is 120 watts.
for 1 phase the vg rating is = 220V
for 3 phase the vg rating is = 440V
i,e,. A = 120 / 220
current drawn for 1 phase is = 0.545 A
current drawn for 3 phase is = 120 / 440 = 0.272 A
I HOPE YOU UNDERSTAND
Current drawn from 220V supply = [bulb 1 current + bulb 2 current] = [(60W/220V) + (60W/220V)] = .(6/11) Amps
We know power=(i^2)r , so here as two bulbs has same power and they are parallel so total
current supplied will distributed among two bulbs evenly.
So here power is directly proportional to resistance.And as 1/R=1/r1 + 1/r2 is net resistance
formula if r1 , r2 are parallel .As power is directly proportional to resistance so,
1/p = 1/p1 + 1/p2 .
so, 1/p = 1/60 +1/60.
thus p=30w.
We also know p=vi => i=p/v => i=30/220=0.136A
This is current thorough circuit.
Current through one bulb = 0.136/2 = 0.068A.
120 / 220 A
