(8^6 / 4^3) must be performed before the multiplication --
just because it "comes first" in the string.
Hence, 8^6/4^3 = (2^18) / (2^6) = 2^12,
and THEN you multiply by 2^5, obtaining 2^17.
So: order of operations is:
do the exponentiations first,
and then do the mult/div in
whatever order they are written,
and the additions and subtractions come last.
Any of these rules can be
"overridden" by parentheses.
Of course, there aren't any additions or
subtractions in your string,
but it's worth learning this as early as possible,
so that you won't be writing 2 + 3/5 + 1
if what you mean is (2+3) / (5+1).
I do not agree with your correct answer. Maybe I don't understand your notation?
(2^3)^6 / (2^2)^3 X 2^5 = 2^18 / 2^6 X 2^5 = 2^7
I'll assume the expression is 8^6÷(4^3×2^5)
8^6 = (2^3)^6 = 2^18
4^3 = (2^2)^3 = 2^6
2^5×2^6 = 2^11
2^18/2^11 = 2^7.....wrong assumption.
I'll try (8^6÷4^3)×2^5 since your expression is posted ambiguously.
2^18/2^6 = 2^12
2^12 × 2^5 = 2^17
Your attempt at solution failed in three spots:
(22)3 = 22×22×22 = 2^6
(21)^5 = 21×21×21×21×21 = 2^5
exponents can't be manipulated unless the bases
are the same.
8^6 can't be divided by 2^11
Your problems will be unnecessarily difficult
with sloppy notation. I pray the Brahman will
grant you tidy notation.
No. 4^3= (2*2)^3= 2*2 * 2*2 * 2*2 = 2^6. 2^5= 2*2*2*2*2>>4^3*2^5= 2^(5+6) = 2^11.
8^6 / 2^11= 1/ 2^5
I'm studying Indices (to the power of) and came across this little confuser of a question.
I worked it out like this,
4^3 x 2^5 = (2^2)^3 x (2^1)^5 = 2^5 x 2^6
Then,
8^6 ÷ 2^11 = 2^5
However,
The correct answer is 2^17. I have not been taught this in class my self but want to know how to do this to get better grades. If anyone can help me do this it would be much appreciated AND a selfless good deed of the day for good karma :D
Thanks,
Sally.
