V = I*R
R = (47*100)/(47 + 100)
R = 31.972789 Ohms
V = 4*(31.972789)
V = 127.891156 Volts
P.47 = V^2/47
P.47 = 16,356.147801/47
P.47 = 348 Watts ............... answer
Current through 47 ohms is 4*100/147= 2.72 amps. Power is I^2R, which you can calculate.348 watts.
I = 4*(100/104)= .385A
P= I^2*R = .385^2*47 = 695.2W
I=I1+I2=4 => I2=4-I1
E=R1*I1=R2*I2 => I1=(R2/R1) * I2 = R1/R2(4-I1)
I1= 47/100(4-I1) simplify to get:
I1 = 188/147 = 1.279A
P = P1=R1 * I1 = 47(ohm) * 1.279(A) = 60.113 = 60 W <= power dissipation on 47 ohm resistor
I believe you need to know the applied voltage
A 47 ! resistor is connected in parallel with a 100 ! resistor and a 4 A current source. How much power is the 47 ohm resistor dissipating?
